Beide Aufgaben werden leicht mit
A) Die Seiten eines Dreiecks sind: b=52mm, c=0,8dm und k=5,8cm. Die
A)
b
=
52
m
m
c
=
0
,
8
d
m
=
80
m
m
{\displaystyle b=52\ mm\quad c=0{,}8\ dm=80\ mm\quad }
k
=
5
,
8
c
m
=
58
m
m
c
′
=
4
,
9
c
m
=
49
m
m
{\displaystyle k=5{,}8\ cm=58\ mm\quad c'=4{,}9\ cm=49\ mm}
c
=
80
↑:
c
′
=
49
⋯
⋯
↙
⋅
⋯
⋯
b
=
52
b
′
{\displaystyle {\begin{matrix}c=80\\\uparrow :\\c'=49\end{matrix}}\quad {\begin{matrix}\cdots \cdots \\\swarrow \cdot \\\cdots \cdots \end{matrix}}\quad {\begin{matrix}b=52\\{}\\b'\end{matrix}}}
(
52
⋅
49
80
)
b
′
≈
32
m
m
{\displaystyle \qquad \left({\frac {52\cdot 49}{80}}\right)\qquad b'\approx 32\ mm}
c
=
80
↑:
c
′
=
49
⋯
⋯
↙
⋅
⋯
⋯
k
=
58
k
′
{\displaystyle {\begin{matrix}c=80\\\uparrow :\\c'=49\end{matrix}}\quad {\begin{matrix}\cdots \cdots \\\swarrow \cdot \\\cdots \cdots \end{matrix}}\quad {\begin{matrix}k=58\\{}\\k'\end{matrix}}}
(
58
⋅
49
80
)
k
′
≈
36
m
m
{\displaystyle \qquad \left({\frac {58\cdot 49}{80}}\right)\qquad k'\approx 36\ mm}
c
=
^
g
b
=
^
d
a
=
^
f
{\displaystyle c{\hat {=}}g\quad b{\hat {=}}d\quad a{\hat {=}}f}
=
^
{\displaystyle {\hat {=}}\ \ }
c
=
78
m
m
d
=
1
,
12
d
m
=
112
m
m
{\displaystyle c=78\ mm\quad d=1{,}12\ dm=112\ mm\quad }
b
=
4
,
4
c
m
=
44
m
m
f
=
9
c
m
=
90
m
m
{\displaystyle b=4{,}4\ cm=44\ mm\quad f=9\ cm=90\ mm}
b
=
44
↑:
d
=
112
⋯
⋯
↙
⋅
⋯
⋯
c
=
78
g
{\displaystyle {\begin{matrix}b=44\\\uparrow :\\d=112\end{matrix}}\quad {\begin{matrix}\cdots \cdots \\\swarrow \cdot \\\cdots \cdots \end{matrix}}\quad {\begin{matrix}c=78\\{}\\g\end{matrix}}}
(
78
⋅
112
44
)
g
≈
199
m
m
{\displaystyle \qquad \left({\frac {78\cdot 112}{44}}\right)\qquad g\approx 199\ mm}
d
=
112
↑:
f
=
90
⋯
⋯
↙
⋅
⋯
⋯
b
=
44
a
{\displaystyle {\begin{matrix}d=112\\\uparrow :\\f=90\end{matrix}}\quad {\begin{matrix}\cdots \cdots \\\swarrow \cdot \\\cdots \cdots \end{matrix}}\quad {\begin{matrix}b=44\\{}\\a\end{matrix}}}
(
44
⋅
90
112
)
a
≈
35
m
m
{\displaystyle \qquad \left({\frac {44\cdot 90}{112}}\right)\qquad a\approx 35\ mm}
